山东2007年造价员考试《建筑工程编制与应用》真题及答案
二、编制图示分部分项工程量清单及分部分项工程量清单计价表(40分)
1、编制内外砖墙分部分项工程量清单(阳台隔墙并入内墙计算)(35分)
序号 |
项目编码 |
项目名称 |
计量单位 |
工程数量 |
1 |
010302001-001 |
实心砖墙 |
M3 |
65.72 |
2 |
010302001-002 |
实心砖墙 |
M3 |
39.15 |
3 |
010302001-003 |
实心砖墙 |
M3 |
1.19 |
计算过程
1.370墙4分
①轴+⑨轴=((2.1+2.4+0.9+0.6+0.25{轴外}×2)×(5.8-0.4{梁高}×2)-(0.9×1.9{C6}))×2=61.58M2
②轴+⑧轴=(5.1+0.37{轴外})×(5.8-0.4{梁高}×2)×2=54.7M2
③轴+⑦轴=((0.9+0.6+0.37{轴外})×(3-0.4{梁高}))×2=9.72M2
④轴+⑥轴=((0.9+0.6+0.37{轴外})×(3-0.4{梁高}))+(0.6+0.37{轴外})×3.6{建施三E轴}×2=16.71M2
A轴=((6-0.12{轴内})×(2.8-0.4{梁高})-(1.2×2.1{C2}+2.4×2.6{TM1}))×2=13.06M2
A轴=((6-0.12{轴内})×(2.8-0.4{梁高})-(1.2×1.9{C4}+2.4×2.4{TM3}))×2=12.14M2
B轴=((1.2-0.37{轴内})×(3.0-0.4{梁高})-(0.83×2.1{C3}))×2=0.83M2
B轴=((1.2-0.37{轴内})×(2.8-0.4{梁高})-(0.83×1.9{C5}))×2=0.83M2
D轴=((2.1-0.25{轴内}×2)×(3.0-0.4{梁高})-(1.2×2.6{M1}))×2=2.08M2
E轴=((2.7-0.12{轴内})×(3.0-0.4{梁高})-(1.5×2.1{C1}))×2=7.12M2
E轴=((2.7-0.12{轴内})×3.6-(1.5×3.6{TM4}))×2=7.78M2
F轴=((2.4-0.12{轴内}×2)×(3.0-0.4{梁高})-(1.2×2.1{C2}))×2=6.19M2
F轴=((2.4+2.1-0.37{轴内})×(0.5+1.9){墙高}-(1.2×1.9{C4})×2)×2=10.7M2
工程量:
(61.58+54.7+9.72+16.71+13.06+12.14+0.83+0.83+2.08+7.12+7.78+6.19+10.7)×0.365=74.26M3
构造柱=0.37×0.37×5{墙体中的柱高}×9{角柱}+0.37×0.37×2.6×2{一层3轴处}+0.37×0.3×5×2{A轴墙中柱}+0.37×0.24×(2.6+3.6){5轴处}=8.53M3
370墙工程量=74.26-8.53=65.72M3
2.240墙4分
③轴+⑦轴=(2.1+2.4-0.25×2{Z1})×(3-0.4{梁高})-(0.8×2.4{M3}+1.8×2.1{TM2})×2=9.40M2
⑤轴=((5.1+2.1+2.4+0.9-0.12{轴内}+2.2{阳台隔墙}+(0.6+1.15){阳台隔墙}-0.37{37墙重合}-0.37×2{构造柱宽})×(3.0-0.4{梁高}))=34.37M2
C轴=(2.4-0.24+1.1-0.25{Z1})×(3.0-0.4{梁高})×2=15.65m2
B轴=(1.2-0.24+1.1-0.25{Z1})×(3.0-0.4{梁高})×2=9.41m2
③轴+⑦轴=(2.1+2.4+0.9+0.6-0.25×2{Z1})×(2.8-0.4{梁高})-(0.8×2.4{M3})×2=22.56M2
⑤轴=((5.1+2.1+2.4+0.9-0.12{轴内}+2.2{阳台隔墙}+(0.6+1.15){阳台隔墙}-0.37{37墙重合}-0.37×2{构造柱宽})×(2.8-0.4{梁高}))=31.73M2
C轴=(2.4+2.1+2.7-0.24×2-0.25{Z1})×(2.8-0.4{梁高})-(0.8×2.4{M3}+0.9×2.4{M2})×2=22.90m2
B轴=(6-0.24-0.25{Z1})×(2.8-0.4{梁高})-(0.8×2.4{M3}+0.9×2.4{M2})×2=17.14m2
240墙工程量:
(9.4+34.37+15.65+9.41+22.56+31.73+22.90+17.14)×0.24=39.15m3
3.120墙1分
(2.4-0.24)×(2.8-0.4{梁高})×0.115×2=1.19m3